Redundant Connection

IF
AlgoAxiomStaff Engineers
JSTS
Medium20 mins

In this problem, a tree is an undirected graph that is connected and has no cycles.

You are given a graph that started as a tree with n nodes labeled from 1 to n, with one additional edge added. The added edge has two different vertices chosen from 1 to n, and was not an edge that already existed. The graph is represented as an array edges of length n where edges[i] = [ai, bi] indicates that there is an edge between nodes ai and bi in the graph.

Return an edge that can be removed so that the resulting graph is a tree of n nodes. If there are multiple answers, return the answer that occurs last in the input.

Examples

Example 1:

Input: edges = [[1,2],[1,3],[2,3]]

Output: [2,3]

Explanation: The edge [2,3] creates a cycle between nodes 1, 2, and 3. Removing it leaves a valid tree.

Example 2:

Input: edges = [[1,2],[2,3],[3,4],[1,4],[1,5]]

Output: [1,4]

Explanation: The edge [1,4] creates a cycle between nodes 1, 2, 3, and 4. Removing it leaves a valid tree.

Example 3:

Input: edges = [[1,2],[1,3],[1,4],[3,4]]

Output: [3,4]

Explanation: The edge [3,4] creates a cycle. Removing it results in a valid tree.

Constraints

  • n == edges.length
  • 3 <= n <= 1000
  • edges[i].length == 2
  • 1 <= ai < bi <= edges.length
  • ai != bi
  • There are no repeated edges.
  • The given graph is connected.
Source: Union Find pattern — AlgoAxiom
JavaScript
Test Case 1
root = [1, 2, 3]
Test Case 2
root = [1, 2, 3, 4, 5]
Idle